A whispering gallery is \(100\) feet long and \(60\) feet wide. Where should the speaker and the listener stand, and how far does the whisper travel on its way across?
Solution.
Model the room as \(\dfrac{x^2}{a^2} + \dfrac{y^2}{b^2} = 1\) with center at the origin. The room is \(100\) feet long and \(60\) feet wide, so \(2a = 100\) and \(2b = 60\text{,}\) giving \(a = 50\) and \(b = 30\text{.}\) Then
\begin{equation*}
c^2 = a^2 - b^2 = 2500 - 900 = 1600 \;\Longrightarrow\; c = 40.
\end{equation*}
The two people should stand at the foci \((\pm 40, 0)\text{,}\) that is, \(40\) feet from the center along the long axis, or \(80\) feet apart. Whatever point of the wall the sound bounces off, it travels a total of \(r_1 + r_2 = 2a = 100\) feet—the same distance every way round, which is exactly why it arrives in phase.

