For the angle between the sides \(\vec{AC}\) and \(\vec{AB}\text{,}\) we have
\begin{equation*}
\begin{aligned}
\vec{AC} \amp = \langle 2-1,\,0+1\rangle = \langle 1,1\rangle \implies |\vec{AC}| = \sqrt2 \\
\vec{AB} \amp = \langle 1-1,\,1+1\rangle = \langle 0,2\rangle \implies |\vec{AB}| = 2 \\
\vec{AB}\cdot\vec{AC} \amp = 0 + 2 = 2 \\
\cos\theta \amp = \frac{\vec{AB}\cdot\vec{AC}}{|\vec{AB}||\vec{AC}|}
= \frac{2}{2\sqrt2} = \frac{1}{\sqrt2} \implies \theta = \frac{\pi}{4}.
\end{aligned}
\end{equation*}