Fix the errors in the code, and change it to use only one if statement. The code should print “The number is 5” when the number is 5, and should print “The number is NOT 5” when it is not.
# Initialize x and set condition for when x = 5
x = 5
if x == 5:
# Indent the body of if statement
print("The number is 5")
# Use else for the secondary condition
else:
# Indent the body of else statement
print("The number is NOT 5")
Complete the pay computation to give the employee 1.5 times the hourly rate for hours worked above 40 hours, if the regular pay rate is $10 an hour. Then set grossPay equal to the amount an employee would be paid for working 45 hours.
# Initializing variables
hours = 45
rate = 10
# overtimeRate is 1.5 the rate amount
overtimeRate = rate * 1.5
grossPay = 0
# Begin conditional to see if hours are within regular pay
if hours <= 40:
#if within 40 hours, pay will be hours * rate
grossPay = hours * rate
# Else statement for when hours are greater than 40
else:
# Create variable for overtime hours
overTime = hours % 40
# Pay will equal the regular rate for 40 hours,
# plus the overtime rate for the extra hours
grossPay = (rate * 40) + (overTime * overtimeRate)
# Print the final pay
print(grossPay)
Rewrite your pay program using try and except so that your program handles non-numeric input gracefully by printing a message and exiting the program. The following shows two executions of the program:
Write the code to calculate and print the cost of a 14 mile cab ride. If the distance traveled is less than or equal to 12 miles the cost is $2.00 a mile, and if the distance traveled is more than 12 miles the cost is $1.50 a mile. Assign the final cost to the variable total.
# distance variable given
distance = 14
# Set conditions
if distance <= 12:
# rate will be 2 if the distance is less than or equal to 12
rate = 2.00
if distance > 12:
# rate will be 1.5 if the distance is greater than 12
rate = 1.50
# Calculate trip cost
total = distance * rate
# Print final statement
print("Total cost of trip: " + str(total))
Write a program to prompt for a score between 0.0 and 1.0. If the score is out of range, print an error message. If the score is between 0.0 and 1.0, print a grade using the following table:
# Initial weight is given
weight = 0.5
# Set conditionals
if weight < 1:
# Set price to 1.45 when weight is less than 1
price = 1.45
# Create condition for when weight is 1
if weight == 1:
# Set price to 0 when weight is 1
price = 0
if weight > 1:
# Set price to 1.15 when weight is greater than 1
price = 1.15
# calculate total using newly assigned variables
total = weight * price
# Print variables
print(weight)
print(price)
print(total)
Write a procedure that takes 2 ints, total price, and amount in wallet. Print “You have enough money” if the difference between the wallet and price is 0 or greater; otherwise, print “Get more money”.
Write a program that takes a year as a parameter and sets leapYear equal to True if the year is a leap year, False otherwise. (use a few different years to test your work)
year = 1900 #TEST WITH ANY YEAR
# Initializing leapYear to False since most years are not leap years
leapYear = False
# Use modulus to see if the year is divisible by 4
if year % 4 == 0:
# If divisible by 4, use modulus to see if divisible by 100
if year % 100 == 0:
# if divisible by 4 and 100, use modulus to see if divisible by 400
if year % 400 == 0:
# if divisible by 4, 100, and 400 it is a leap year
leapYear = True
else: # if divisible by 4 and not 100 it is a leap year
leapYear = True
print(leapYear)
''' Since leapYear started as False, we do not need to reset it to False
for the instances that the year is not a leap year '''
# ANOTHER OPTION
year = 1900
leapYear = False
if year % 400 == 0:
leapYear = True
elif year % 4 == 0 and year % 100 != 0:
leapYear = True
print(leapYear)
Finish the following code. It first sets n to a number input by a user. Convert the number from a string to an integer and set result to True if the number is an even number (evenly divisible by two) and False if it is odd. Note: use the modulo operator.
