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Section 5.23 Functions and Strings Multiple Choice Questions

Activity 5.23.1.

Given the below code snippet, which of the following options would create a variable called final_string that is assigned to the word “yelling”? 
string1 = "yellow"
string2 = "screaming"
  • final_string = string1[:4] + string2[-3:]
  • Correct! Using the slice operator [start:end], the starting index is inclusive, while the ending index is exclusive.
  • final_string = string1[:4] + string2[6:]
  • Correct! Using the slice operator [start:end], the starting index is inclusive, while the ending index is exclusive.
  • final_string = string1[:3] + string2[6:]
  • Try again! This would assign final_string to "yeling".
  • final_string = string1[:3] + string2[6:-1]
  • Try again! This would assign final_string to "yelin".
  • final_string = string1[:4].append(string2[-3:])
  • Try again! String objects do not have the attribute "append".

Activity 5.23.2.

Which of the following choices correctly prints a sentence using the variable num_of_apples? 
num_of_apples = 4
  • print("I have " + num_of_apples + " apples.")
  • Try again! You can’t concatenate a string and an integer together.
  • print("I have " + str("num_of_apples") + " apples.")
  • Try again! Do not enclose the variable name in a string or you will get just those characters.
  • print("I have 4 apples.")
  • Try again! This doesn’t use the variable num_of_apples.
  • print("I have " + str(num_of_apples) + " apples.")
  • Correct! By using str, the integer variable is converted into a string.

Activity 5.23.3.

Which of the following are string methods?
  • split()
  • Correct!
  • lower()
  • Correct!
  • append()
  • Try again! This is a list method, not a string method.
  • startswith()
  • Correct!
  • sort()
  • Try again! This is a list method, not a string method.

Activity 5.23.4.

Which of the following code corresponds to the amount of characters in the following string variable? 
string = "I love coding!"
  • count(string)
  • Try again! Count is a python string method that counts the amount of occurrences of a substring.
  • len(string)
  • Correct!
  • int(string)
  • Try again! String with words cannot be converted to ints.
  • length(string)
  • Try again! Instead of length, it should be len, because length is not a built-in python function.

Activity 5.23.5.

What does the following code output? 
def abbrev(first_name, last_name):
   print(first_name[0:1] + ". " + last_name.lower())

abbrev("Joanne", "Weathers")
  • J. Weathers
  • Try again! The first letter in the last name should be lowercase.
  • Jo. Weathers
  • Try again! The end of a slice operator is exclusive (e.g., 1 is exclusive in this example).
  • oa. Weathers
  • Try again! Strings are indexed starting at 0.
  • J. weathers
  • Correct!
  • j. weathers
  • Try again! Only the last name should be lowercase.

Activity 5.23.6.

After running this code, what would be the output if the input was first_name = "Katie" and last_name = "perkins"? 
def abbrev():
   first_name = input("What is your first name? ")
   last_name = input("What is your last name? ")
   return("Hello " + first_name + last_name[0:2].capitalize() + ". ")

def main():
   abbrev()

main()
  • Hello KatiePe.
  • Try again! This would be correct if there was a print statement.
  • Nothing.
  • Correct! Nothing would be outputted because there is no print statement.
  • Hello Katie Pe.
  • Try again! There shouldn’t be a space between the first and last name.
  • Hello KatiePE.
  • Try again! The E should not be capitalized. The upper() method would capitalize the E, but not the capitalize() method.

Activity 5.23.7.

Given the variable item, how would you grab the letters “tebo”? 
def notebook():
   item = "notebook"
   # What goes here?

notebook()
  • print(item[2:7])
  • Try again! This would print "teboo".
  • print(item[2:6])
  • Correct!
  • print(item[-6:-2])
  • Correct!
  • print(item[3] + item[4] + item[5] + item[6])
  • Try again! This would print "eboo".
  • print(item[3:7])
  • Try again! This would print "eboo".
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