There is a function we are providing in for you in this problem called square. It takes one integer and returns the square of that integer value. Write code to assign a variable called xyz the value 5*5 (five squared). Use the square function, rather than just multiplying with *.
Checkpoint2.17.2.
Write code to assign the number of characters in the string rv to a variable num_chars.
Checkpoint2.17.3.
The code below initializes two variables, z and y. We want to assign the total number of characters in z and in y to the variable a. Which of the following solutions, if any, would be considered hard coding?
z = "hello world"
y = "welcome!"
a = len("hello worldwelcome!")
Though we are using the len function here, we are hardcoding what len should return the length of. We are not referencing z or y.
a = 11 + 8
This is hardcoding, we are writing in the value without referencing z or y.
a = len(z) + len(y)
This is not considered hard coding. We are using the function len to determine the length of what is stored in z and y, which is a correct way to approach this problem.
a = len("hello world") + len("welcome!")
Though we are using the len function here, we are hardcoding what len should return the length of each time we call len. We are not referencing z or y.
none of the above are hardcoding.
At least one of these solutions is considered hardcoding. Take another look.