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2.18. Chapter 2 Assessment

Check your understanding

There is a function we are providing in for you in this problem called square. It takes one integer and returns the square of that integer value. Write code to assign a variable called xyz the value 5*5 (five squared). Use the square function, rather than just multiplying with *.

xyz = "" ===== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(type(xyz), type(3), "Checking type of xyz") self.assertEqual(xyz, 25, "Checking if xyz is 25") self.assertIn('square', self.getEditorText(), "Testing that 'square' is in your code. (Don't worry about Actual and Expected Values.)") myTests().main()

Write code to assign the number of characters in the string rv to a variable num_chars.

rv = """Once upon a midnight dreary, while I pondered, weak and weary, Over many a quaint and curious volume of forgotten lore, While I nodded, nearly napping, suddenly there came a tapping, As of some one gently rapping, rapping at my chamber door. 'Tis some visitor, I muttered, tapping at my chamber door; Only this and nothing more.""" # Write your code here! ===== from unittest.gui import TestCaseGui class myTests(TestCaseGui): def testOne(self): self.assertEqual(num_chars, len(rv), "Testing that num_chars has been set to the length of rv") myTests().main()

The code below initializes two variables, z and y. We want to assign the total number of characters in z and in y to the variable a. Which of the following solutions, if any, would be considered hard coding?

z = "hello world"
y = "welcome!"

• a = len("hello worldwelcome!")
• Though we are using the len function here, we are hardcoding what len should return the length of. We are not referencing z or y.
• a = 11 + 8
• This is hardcoding, we are writing in the value without referencing z or y.
• a = len(z) + len(y)
• This is not considered hard coding. We are using the function len to determine the length of what is stored in z and y, which is a correct way to approach this problem.
• a = len("hello world") + len("welcome!")
• Though we are using the len function here, we are hardcoding what len should return the length of each time we call len. We are not referencing z or y.
• none of the above are hardcoding.
• At least one of these solutions is considered hardcoding. Take another look.

(This is not an assessment question) The code below defines functions used by one of the questions above. Do not modify the code, but feel free to take a look.

def square(num): return num**2

Which variables in the image above are assigned string values? List each variable in the box below, separated by a white space.

Which line number(s) will print an integer as the result of the given operation? List each line number in the box below, separated by a COMMA.

The image above shows a program that just completed executing (we know this because the green arrow is on the last line and there is no red arrow in the image). At the end of the program, which variables changed from their original value during the program’s execution? List each variable in the box below, separated by a white space.

:



What does the following code shown in the codelens image print when it finishes executing?

• an error
• This is a correct. When using + to stick strings together, all variables need to be a string. This throws a type error.
• sara 11
• Hmm, this would be true if 11 was a string but it isn't
• sara11
• Hmm, not quite, we stick a space on our string in line 3
• "sara11"
• Hmm, not quite, we stick a space on our string in line 3 and we don't have quotes
• "sara 11"
• Hmm, we don't have quotes in our string

:



Here is that same image of code again. Which line number shows a line of code we would define as an expression?

• 1
• This is a variable being asssigned a string value
• 2
• This is a variable being assigned an integer value
• 3
• Correct, "sara" + " " + age is an expression that we want to evaluate to "sara 11" and store the string in the info variable
• 4
• This prints the string value stored the info variable

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