5.8. Easy Multiple Choice Questions

These problems are easier than most of those that you will usually see on the AP CS A exam.

    5-8-1: What does the following code print when x has been set to 187?

    if (x < 0) System.out.println("x is negative");
    else if (x == 0) System.out.println("x is zero");
    else System.out.println("x is positive");
    
  • x is negative
  • This will only print if x has been set to a number less than zero. Has it?
  • x is zero
  • This will only print if x has been set to 0. Has it?
  • x is positive
  • The first condition is false and x is not equal to zero so the else will execute.

    5-8-2: What is printed when the following code executes and x equals 4 and y equals 3?

    if (!(x < 3 || y > 2)) System.out.println("first case");
    else System.out.println("second case");
    
  • first case
  • This will print if x is greater than or equal 3 and y is less than or equal 2. In this case x is greater than 3 so the first condition is true, but the second condition is false.
  • second case
  • This will print if x is less than 3 or y is greater than 2.

    5-8-3: What is the value of grade when the following code executes and score is 80?

    if (score >= 90) grade = "A";
    if (score >= 80) grade = "B";
    if (score >= 70) grade = "C";
    if (score >= 60) grade = "D";
    else grade = "E";
    
  • A
  • Notice that each of the first 4 statements start with an if. What will actually be printed? Try it.
  • B
  • Each of the first 4 if statements will execute.
  • C
  • Check this in DrJava.
  • D
  • Each of the if statements will be executed. So grade will be set to B then C and finally D.
  • E
  • This will only be true when score is less than 60.

    5-8-4: What is printed when the following code executes and x has been set to zero and y is set to 3?

    if (x > 0 || (y / x) == 3) System.out.println("first case");
    else System.out.println("second case");
    
  • first case
  • This will print if either of the two conditions are true. The first isn't true but the second will cause an error.
  • second case
  • This will print if both of the conditions are false. But, an error will occur when testing the second condition.
  • You will get a error because you can't divide by zero.
  • The first condition will be false so the second one will be executed and lead to an error since you can't divide by zero.
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