12.5. Building a Simulation - 2

Now that we have a working function, we can focus on using the function. Look for the spot with missing code at line 28. Add the needed code to complete the accumulator pattern to count up the number of times result ends up as True. The expected answer is around 80% - about 8 times out of 10 you should get at least 5 heads in a row if you flip a coin 100 times.

If you run into troubles, here are some debugging tips:

• We know checkHeadsInRow works. Focus your attention on the main part of the program.

• Print the result you get in each repetition loop.

• Print the successCounter at the end of each repetition of the loop.

• Reduce repetitions to something like 10 to make it easier to see all the output. Your answer will be less reliable with fewer repetitions, so reset it to 10000 when you are done debugging.

import random def checkHeadsInRow(desiredStreak): headsInARow = 0 #start with 0 for i in range(100): flip = random.randrange(0, 2) if flip == 0: headsInARow = headsInARow + 1 else: headsInARow = 0 if headsInARow == desiredStreak: break # Make final decision if headsInARow >= desiredStreak: return True else: return False # --------------------------------- # main part of program repetitions = 10000 successCounter = 0 for run in range(repetitions): # use the function to see if we get the 5 heads in a row result = checkHeadsInRow(5) # TODO if result is True increase successCounter by 1 print("The successCounter is", successCounter) print("As a percent, that is:") percent = (successCounter / repetitions) * 100 print(str(percent) + "%")

Change the program to check the odds of getting 6 heads in a row in 100 flips. Make sure to use 10,000 repetitions so your answer is reliable. What answer do you get? Round it to the nearest whole number.

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