Skip to main content
Contents Index
Search Book
Search Results:
No results.
Read aloud
Readability settings Prev Up Next Scratch ActiveCode Profile
title here
\(\newcommand{\set}[1]{\{#1\}}
\newcommand{\ints}{\mathbb{Z}}
\newcommand{\posints}{\mathbb{N}}
\newcommand{\rats}{\mathbb{Q}}
\newcommand{\reals}{\mathbb{R}}
\newcommand{\complexes}{\mathbb{C}}
\newcommand{\twospace}{\mathbb{R}^2}
\newcommand{\threepace}{\mathbb{R}^3}
\newcommand{\dspace}{\mathbb{R}^d}
\newcommand{\nni}{\mathbb{N}_0}
\newcommand{\nonnegints}{\mathbb{N}_0}
\newcommand{\dom}{\operatorname{dom}}
\newcommand{\ran}{\operatorname{ran}}
\newcommand{\prob}{\operatorname{prob}}
\newcommand{\Prob}{\operatorname{Prob}}
\newcommand{\height}{\operatorname{height}}
\newcommand{\width}{\operatorname{width}}
\newcommand{\length}{\operatorname{length}}
\newcommand{\crit}{\operatorname{crit}}
\newcommand{\inc}{\operatorname{inc}}
\newcommand{\HP}{\mathbf{H_P}}
\newcommand{\HCP}{\mathbf{H^c_P}}
\newcommand{\GP}{\mathbf{G_P}}
\newcommand{\GQ}{\mathbf{G_Q}}
\newcommand{\AG}{\mathbf{A_G}}
\newcommand{\GCP}{\mathbf{G^c_P}}
\newcommand{\PXP}{\mathbf{P}=(X,P)}
\newcommand{\QYQ}{\mathbf{Q}=(Y,Q)}
\newcommand{\GVE}{\mathbf{G}=(V,E)}
\newcommand{\HWF}{\mathbf{H}=(W,F)}
\newcommand{\bfC}{\mathbf{C}}
\newcommand{\bfG}{\mathbf{G}}
\newcommand{\bfH}{\mathbf{H}}
\newcommand{\bfF}{\mathbf{F}}
\newcommand{\bfI}{\mathbf{I}}
\newcommand{\bfK}{\mathbf{K}}
\newcommand{\bfP}{\mathbf{P}}
\newcommand{\bfQ}{\mathbf{Q}}
\newcommand{\bfR}{\mathbf{R}}
\newcommand{\bfS}{\mathbf{S}}
\newcommand{\bfT}{\mathbf{T}}
\newcommand{\bfNP}{\mathbf{NP}}
\newcommand{\bftwo}{\mathbf{2}}
\newcommand{\cgA}{\mathcal{A}}
\newcommand{\cgB}{\mathcal{B}}
\newcommand{\cgC}{\mathcal{C}}
\newcommand{\cgD}{\mathcal{D}}
\newcommand{\cgE}{\mathcal{E}}
\newcommand{\cgF}{\mathcal{F}}
\newcommand{\cgG}{\mathcal{G}}
\newcommand{\cgM}{\mathcal{M}}
\newcommand{\cgN}{\mathcal{N}}
\newcommand{\cgP}{\mathcal{P}}
\newcommand{\cgR}{\mathcal{R}}
\newcommand{\cgS}{\mathcal{S}}
\newcommand{\bfn}{\mathbf{n}}
\newcommand{\bfm}{\mathbf{m}}
\newcommand{\bfk}{\mathbf{k}}
\newcommand{\bfs}{\mathbf{s}}
\newcommand{\bijection}{\xrightarrow[\text{onto}]{\text{$1$--$1$}}}
\newcommand{\injection}{\xrightarrow[]{\text{$1$--$1$}}}
\newcommand{\surjection}{\xrightarrow[\text{onto}]{}}
\newcommand{\nin}{\not\in}
\newcommand{\prufer}{\text{prüfer}}
\DeclareMathOperator{\fix}{fix}
\DeclareMathOperator{\stab}{stab}
\DeclareMathOperator{\var}{var}
\newcommand{\inv}{^{-1}}
\newcommand{\ds}{\displaystyle}
\newcommand{\mbf}[1]{\mathbf{#1}}
\newcommand{\mc}[1]{\mathcal{#1}}
\newcommand{\lt}{<}
\newcommand{\gt}{>}
\newcommand{\amp}{&}
\definecolor{fillinmathshade}{gray}{0.9}
\newcommand{\fillinmath}[1]{\mathchoice{\colorbox{fillinmathshade}{$\displaystyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\textstyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\scriptstyle \phantom{\,#1\,}$}}{\colorbox{fillinmathshade}{$\scriptscriptstyle\phantom{\,#1\,}$}}}
\)
Section 3.6 Mathematical Induction
Now we move on to induction, the powerful twin of recursion.
Let \(n\) be a positive integer. Consider the following mathematical statements, each of which involve \(n\text{:}\)
\(2n+7 = 13\text{.}\)
\(3n-5=9\text{.}\)
\(n^2-5n+9=3\text{.}\)
\(8n-3 \lt 48\text{.}\)
\(8n-3 > 0\text{.}\)
\((n+3)(n+2) =n^2+5n+6\text{.}\)
\(n^2 -6n + 13 \ge 0\text{.}\)
Such statements are called
open statements . Open statements can be considered as
equations , i.e., statements that are valid for certain values of
\(n\text{.}\) Statement 1 is valid only when
\(n=3\text{.}\) Statement 2 is never valid, i.e., it has no solutions among the positive integers. Statement 3 has exactly two solutions, and Statement 4 has six solutions. On the other hand, Statements 5, 6 and 7 are valid for all positive integers.
At this point, you are probably scratching your head, thinking that this discussion is trivial. But let’s consider some statements that are a bit more complex.
The sum of the first
\(n\) positive integers is
\(n(n+1)/2\text{.}\)
The sum of the first
\(n\) odd positive integers is
\(n^2\text{.}\)
\(n^n \ge n! + 4,000,000,000n2^n\) when
\(n\ge 14\text{.}\)
How can we establish the validity of such statements, provided of course that they are actually true? The starting point for providing an answer is the following property:
Principle 3.11 Principle of Mathematical Induction.
Let
\(S_n\) be an open statement involving a positive integer
\(n\text{.}\) If
\(S_1\) is true, and if for each positive integer
\(k\text{,}\) assuming that the statement
\(S_k\) is true implies that the statement
\(S_{k+1}\) is true, then
\(S_n\) is true for every positive integer
\(n\text{.}\)
You have attempted
of
activities on this page.