{Many|All|Several} of `person(1)`'s friends wanted to try the candy bars
`he(1)` brought back from `his(1)` trip, but there were only `PIECES` candy bars.
`person(1)` decided to cut the candy bars into pieces so that each person could have
`\frac{`

of a candy bar.
`N`}{`D`}

After cutting up the candy bars, how many friends could `person(1)` share `his(1)` candy with?

We can divide the number of candy bars (

) by the amount `PIECES``person(1)` gave to each person
(`\frac{`

of a bar) to find out how many people `N`}{`D`}`he(1)` could share with.

```
\dfrac{\color{
```

`ORANGE`}{`PIECES` \text{ candy bars}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ bar per person}}} = \color{`PINK`}{\text{ total people}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ bar per person}`\dfrac{`

.
`D`}{`N`} \text{ people per bar}

```
\color{
```

`ORANGE`}{`PIECES`\text{ candy bars}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ people per bar}}
= \color{`PINK`}{\text{total people}}

`\color{`

`PINK`}{\dfrac{`D * PIECES`}{`N`}\text{ people}} = `SOLUTION`\text{ people}

`person(1)` just found beautiful yarn {for `randFromArray([5,20])` percent off }at
`his(1)` favorite yarn store.
`He(1)` can make 1 scarf from `\frac{`

of a ball of yarn.
`N`}{`D`}

If `person(1)` buys `YARN` balls of yarn, how many scarves can `he(1)` make?

We can divide the balls of yarn (`YARN`) by the yarn needed per scarf (`\frac{`

of
a ball) to find out how many scarves `N`}{`D`}`person(1)` can make.

```
\dfrac{\color{
```

`ORANGE`}{`YARN` \text{ balls of yarn}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ ball per scarf}}} = \color{`PINK`}{\text{ number of scarves}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ ball per scarf}`\dfrac{`

.
`D`}{`N`} \text{ scarves per ball}

```
\color{
```

`ORANGE`}{`YARN`\text{ balls of yarn}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ scarves per ball}}
= \color{`PINK`}{\text{ number of scarves}}

`\color{`

`PINK`}{\dfrac{`D * YARN`}{`N`}\text{ scarves}} = `SOLUTION`\text{ scarves}

`person(1)` can make `SOLUTION` scarves.

`person(1)` decided to paint some of the rooms at `his(1)` `ROOM`-room inn,
`person(1)`'s Place. `He(1)` discovered `he(1)` needed `\frac{`

of a can of paint per room.
`N`}{`D`}

If `person(1)` had `PAINT` cans of paint, how many rooms could `he(1)` paint?

We can divide the cans of paint (`PAINT`) by the paint needed per room (`\frac{`

of
a can) to find out how many rooms `N`}{`D`}`person(1)` could paint.

```
\dfrac{\color{
```

`ORANGE`}{`PAINT` \text{ cans of paint}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ can per room}}} = \color{`PINK`}{\text{ rooms}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ can per room}`\dfrac{`

.
`D`}{`N`} \text{ rooms per can}

```
\color{
```

`ORANGE`}{`PAINT`\text{ cans of paint}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ rooms per can}}
= \color{`PINK`}{\text{ rooms}}

`\color{`

`PINK`}{\dfrac{`D * PAINT`}{`N`}\text{ rooms}} = `SOLUTION`\text{ rooms}

`person(1)` could paint `SOLUTION` rooms.

As the swim coach at `school(1)`, `person(1)` selects which athletes will participate in the state-wide swim relay.

The relay team swims `\frac{`

of a mile all together, with each team
member responsible for swimming `A`}{`B`}`\frac{`

of a mile.
The team must complete the swim in `N`}{`D`}`\frac{3}{`

of an hour.
`randRange(4,5)`}

How many swimmers does `person(1)` need on the relay team?

To find out how many swimmers `person(1)` needs on the team, divide the total distance
(`\frac{`

of a mile) by the distance each team member will swim
(`A`}{`B`}`\frac{`

of a mile).
`N`}{`D`}

```
\dfrac{\color{
```

`ORANGE`}{\dfrac{`A`}{`B`} \text{ mile}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ mile per swimmer}}} = \color{`PINK`}{\text{ number of swimmers}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ mile per swimmer}`\dfrac{`

.
`D`}{`N`} \text{ swimmers per mile}

```
\color{
```

`ORANGE`}{\dfrac{`A`}{`B`}\text{ mile}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ swimmers per mile}}
= \color{`PINK`}{\text{ number of swimmers}}

```
\dfrac{\color{
```

`ORANGE`}{`A`} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{`N`}}
= \color{`PINK`}{\text{ number of swimmers}}

Reduce terms with common factors by dividing the

in the numerator
and the `A`

in the denominator by `N`

:
`GCD1`

```
\dfrac{\color{
```

`ORANGE`}{\cancel{`A`}^{`SIMP_A`}} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{\cancel{`N`}^{`SIMP_N`}}}
= \color{`PINK`}{\text{ number of swimmers}}

Reduce terms with common factors by dividing the

in the numerator
and the `D`

in the denominator by `B`

:
`GCD2`

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{\cancel{`D`}^{`SIMP_D`}}}
{\color{`ORANGE`}{\cancel{`B`}^{`SIMP_B`}} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{\text{ number of swimmers}}

Simplify:

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{`SIMP_D`}}
{\color{`ORANGE`}{`SIMP_B`} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{`SOLUTION`}

`person(1)` needs `SOLUTION` swimmers on `his(1)` team.

`person(1)` thought it would be nice to include `\frac{`

of a pound of chocolate in each
of the holiday gift bags `N`}{`D`}`he(1)` made for `his(1)` friends and family.

How many holiday gift bags could `person(1)` make with `\frac{`

of a pound of chocolate?`A`}{`B`}

To find out how many gift bags `person(1)` could create, divide the total chocolate
(`\frac{`

of a pound) by the amount `A`}{`B`}`he(1)` wanted to include in each gift bag
(`\frac{`

of a pound).
`N`}{`D`}

```
\dfrac{\color{
```

`ORANGE`}{\dfrac{`A`}{`B`} \text{ pound of chocolate}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ pound per bag}}} = \color{`PINK`}{\text{ number of bags}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ pound per bag}`\dfrac{`

.
`D`}{`N`} \text{ bags per pound}

```
\color{
```

`ORANGE`}{\dfrac{`A`}{`B`}\text{ pound}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ bags per pound}}
= \color{`PINK`}{\text{ number of bags}}

```
\dfrac{\color{
```

`ORANGE`}{`A`} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{`N`}}
= \color{`PINK`}{\text{ number of bags}}

Reduce terms with common factors by dividing the

in the numerator
and the `A`

in the denominator by `N`

:
`GCD1`

```
\dfrac{\color{
```

`ORANGE`}{\cancel{`A`}^{`SIMP_A`}} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{\cancel{`N`}^{`SIMP_N`}}}
= \color{`PINK`}{\text{ number of bags}}

Reduce terms with common factors by dividing the

in the numerator
and the `D`

in the denominator by `B`

:
`GCD2`

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{\cancel{`D`}^{`SIMP_D`}}}
{\color{`ORANGE`}{\cancel{`B`}^{`SIMP_B`}} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{\text{ number of bags}}

Simplify:

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{`SIMP_D`}}
{\color{`ORANGE`}{`SIMP_B`} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{`SOLUTION`}

`person(1)` could create `SOLUTION` gift bags.

`person(1)` works out for `\frac{`

of an hour every day. To keep `A`}{`B`}`his(1)`
exercise routines interesting, `he(1)` includes different types of exercises, such as
`plural(exercise(1))` and `plural(exercise(2))`, in each workout.

If each type of exercise takes `\frac{`

of an hour, how many different types of
exercise can `N`}{`D`}`person(1)` do in each workout?

To find out how many types of exercise `person(1)` could do in each workout, divide
the total amount of exercise time (`\frac{`

of an hour) by the amount of
time each exercise type takes (`A`}{`B`}`\frac{`

of an hour).
`N`}{`D`}

```
\dfrac{\color{
```

`ORANGE`}{\dfrac{`A`}{`B`} \text{ hour}}}
{\color{`BLUE`}{\dfrac{`N`}{`D`} \text{ hour per exercise}}} = \color{`PINK`}{\text{ number of exercises}}

Dividing by a fraction is the same as multiplying by the reciprocal.

The reciprocal of `\dfrac{`

is `N`}{`D`} \text{ hour per exercise}`\dfrac{`

.
`D`}{`N`} \text{ exercises per hour}

```
\color{
```

`ORANGE`}{\dfrac{`A`}{`B`}\text{ hour}} \times
\color{`GREEN`}{\dfrac{`D`}{`N`} \text{ exercises per hour}}
= \color{`PINK`}{\text{ number of exercises}}

```
\dfrac{\color{
```

`ORANGE`}{`A`} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{`N`}}
= \color{`PINK`}{\text{ number of exercises}}

Reduce terms with common factors by dividing the

in the numerator
and the `A`

in the denominator by `N`

:
`GCD1`

```
\dfrac{\color{
```

`ORANGE`}{\cancel{`A`}^{`SIMP_A`}} \cdot \color{`GREEN`}{`D`}}
{\color{`ORANGE`}{`B`} \cdot \color{`GREEN`}{\cancel{`N`}^{`SIMP_N`}}}
= \color{`PINK`}{\text{ number of exercises}}

Reduce terms with common factors by dividing the

in the numerator
and the `D`

in the denominator by `B`

:
`GCD2`

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{\cancel{`D`}^{`SIMP_D`}}}
{\color{`ORANGE`}{\cancel{`B`}^{`SIMP_B`}} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{\text{ number of exercises}}

Simplify:

```
\dfrac{\color{
```

`ORANGE`}{`SIMP_A`} \cdot \color{`GREEN`}{`SIMP_D`}}
{\color{`ORANGE`}{`SIMP_B`} \cdot \color{`GREEN`}{`SIMP_N`}}
= \color{`PINK`}{`SOLUTION`}

`person(1)` can do `SOLUTION` different types of exercise per workout.