randRangeUnique( 1, 8, 5 ) randFromArray([ "meteorite", "moon", "earth" ]) "<img src='" + Khan.urlBase + "images/" + BADGE + "-small.png'>" 1

Use the pictograph to answer the question below:

BADGE badges earned by each student
person( n + 1 )FULL_IMAGE  
FULL_IMAGE = VALUE_PER_IMG BADGE plural( "badge", VALUE_PER_IMG )
_.indexOf( DATA, Math.max.apply( Math, DATA ) )

Who earned the most BADGE badges?

person( MOST + 1 )
  • person( 1 )
  • person( 2 )
  • person( 3 )
  • person( 4 )
  • person( 5 )

Who has the largest number of BADGE symbols next to his( MOST + 1 ) name in the chart?

person( MOST + 1 ) has the largest number of symbols next to his( MOST + 1) name.

person( MOST + 1 ) earned the most BADGE badges.

_.indexOf( DATA, Math.min.apply( Math, DATA ) )

Who earned the fewest BADGE badges?

person( LEAST + 1 )
  • person( 1 )
  • person( 2 )
  • person( 3 )
  • person( 4 )
  • person( 5 )

Who has the smallest number of BADGE symbols next to his( LEAST + 1 ) name in the chart?

person( LEAST + 1 ) has the smallest number of symbols next to his( LEAST + 1) name.

person( LEAST + 1 ) earned the fewest BADGE badges.

rand( 5 ) DATA[ PERSON ] * VALUE_PER_IMG

How many BADGE badges did person( PERSON + 1 ) earn?

ANSWER

The key at the bottom of the pictograph shows that each symbol represents plural( VALUE_PER_IMG, "badge" ).

Find person( PERSON + 1 )'s row in the table:
person( PERSON + 1 )FULL_IMAGE  

There plural( "is", DATA[PERSON] ) plural( DATA[ PERSON ], "symbol" ).

DATA[ PERSON ] plural( "symbol", DATA[ PERSON ] ) \times VALUE_PER_IMG plural( "badge", VALUE_PER_IMG ) per symbol = DATA[ PERSON ] * VALUE_PER_IMG plural( "badge", DATA[ PERSON ] * VALUE_PER_IMG ).

person( PERSON + 1 ) earned ANSWER BADGE plural( "badge", ANSWER ).